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#9
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And the answer is....8
![]() ![]() For any 2 cards, either 87 ![]() ![]() ![]() ![]() I wonder why 8's have the advantage over 7's, is it because of the 2 pair possibilities? The ace kicker is going to win in all 2 pair situations with the 2 pair on the board being higher than 8s, and having 8s is better than 7s in that situation.
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